Previous-year papers show how GATE Civil Engineering mixes its eight sections in one sitting. This page sets out the current CE pattern, where the official Civil papers and answer keys are published and how to use them by section, then 12 original practice questions with full solutions. For structured practice across all eight sections, see the Myndaq GATE CE course.
The GATE CE paper pattern
As published by IIT Madras (pattern page and brochure), read on 16 September 2026:
- 65 questions, 100 marks, 3 hours - computer-based, in a forenoon (9:30 AM to 12:30 PM) or afternoon (2:30 PM to 5:30 PM) session
- General Aptitude - 10 questions for 15 marks
- Subject component - 55 questions for 85 marks; in CE, Engineering Mathematics carries 13 of those marks and core civil topics 72
- Question types - 1- or 2-mark MCQ (four options, one correct), MSQ (four options, one or more correct) and NAT (a signed real number entered on the on-screen numeric keypad)
- Marking - a wrong 1-mark MCQ loses 1/3 mark and a wrong 2-mark MCQ loses 2/3; MSQ and NAT carry no negative marks, and no question earns partial marks
- Calculator - only the on-screen virtual calculator
See the marking scheme guide and NAT and virtual calculator strategy.
Where the official Civil papers and answer keys are published
- Official GATE Downloads page - a bulk download of papers from 2007 to 2026, plus year-wise papers with answer keys for 2021 to 2026. Civil Engineering is a single paper in 2021 and 2022 and two sets, CE-1 and CE-2, in each year from 2023 to 2026.
- GATE 2026 page at IIT Guwahati - lists CE-1 (forenoon) and CE-2 (afternoon), each with its own master question paper and key. On-screen question order may differ from the master paper, so check answers against the master paper and its key.
No official question is reproduced here. Two cautions:
- Treat CE-1 and CE-2 as separate full papers. Each has its own key; for how raw marks become a score, see marks versus GATE score and the GATE score calculator.
- Check old questions against the current syllabus. IIT Madras has published revised syllabi. The GATE CE syllabus guide walks through the official PDF; set aside questions on topics it omits.
How to use CE previous-year questions, section by section
Work in two passes: untimed by section until your method is reliable, then full timed sets, logging every lost mark by section and cause.
- Engineering Mathematics - drill numerical methods, ODEs and probability for speed.
- Structural Engineering - sketch free-body and bending moment diagrams first.
- Geotechnical Engineering - draw the soil profile with the water table before computing stresses.
- Water Resources Engineering - keep a values-and-units page of key relations.
- Environmental Engineering - convert MLD to cubic metres per day first.
- Transportation Engineering - convert km/h to m/s before sight-distance work.
- Geomatics Engineering - book levelling data in a table and check it arithmetically.
- Construction Materials and Management - mark early and late times on every CPM network.
Original practice questions in the GATE CE style
The 12 questions below are original practice questions written by Myndaq in the official GATE style. They are not official past-paper questions.
Q1 - Engineering Mathematics, NAT, 1 mark
Using the trapezoidal rule with four equal intervals, the integral of x² from x = 0 to x = 2, rounded off to two decimal places, is ____.
Answer: 2.75. With h = 0.5, the ordinates are 0, 0.25, 1, 2.25 and 4. The rule gives (h/2) × [0 + 2(0.25 + 1 + 2.25) + 4] = 0.25 × 11 = 2.75, slightly above the exact 8/3.
Q2 - Engineering Mathematics, MCQ, 2 marks
The solution of y'' + 4y' + 4y = 0 with y(0) = 1 and y'(0) = 0 is:
- (A) (1 + 2x)e^(−2x)
- (B) (1 − 2x)e^(−2x)
- (C) (1 + x)e^(−2x)
- (D) e^(−2x) cos 2x
Answer: (A). The auxiliary equation has the repeated root m = −2, so y = (c₁ + c₂x)e^(−2x). y(0) = 1 gives c₁ = 1, and y'(0) = c₂ − 2c₁ = 0 gives c₂ = 2.
Q3 - Structural Engineering, NAT, 2 marks
A simply supported beam of span 4 m carries a central point load of 50 kN. With E = 200 GPa and I = 8 × 10⁷ mm⁴, ignoring self-weight, the midspan deflection in mm, rounded off to two decimal places, is ____.
Answer: 4.17. The deflection is PL³/(48EI). In N and mm, PL³ = 50,000 × 4000³ = 3.2 × 10¹⁵ and 48EI = 48 × 200,000 × 8 × 10⁷ = 7.68 × 10¹⁴, giving 4.1667 mm.
Q4 - Structural Engineering, MSQ, 2 marks
In plane stress, σx = 80 MPa (tension), σy = 20 MPa (tension) and τxy = 40 MPa. Which are correct?
- (A) The major principal stress is 100 MPa
- (B) The minor principal stress is zero
- (C) The maximum in-plane shear stress is 40 MPa
- (D) The normal stress on the planes of maximum in-plane shear is 30 MPa
Answer: (A) and (B). Mohr's circle has centre (80 + 20)/2 = 50 MPa and radius √(30² + 40²) = 50 MPa, so σ₁ = 100 MPa and σ₂ = 0. The maximum in-plane shear is the radius, 50 MPa, and the normal stress on those planes is the centre value, 50 MPa, so (C) and (D) are false.
Q5 - Geotechnical Engineering, NAT, 1 mark
A saturated soil has void ratio 0.6 and specific gravity of solids 2.7. Taking γw = 9.81 kN/m³, its saturated unit weight in kN/m³, rounded off to two decimal places, is ____.
Answer: 20.23. γsat = (G + e)γw/(1 + e) = 3.3 × 9.81/1.6 = 20.233 kN/m³.
Q6 - Geotechnical Engineering, MCQ, 2 marks
In a sand deposit the water table is 2 m below ground. Above it the sand is dry with unit weight 16 kN/m³; below it the saturated unit weight is 20 kN/m³. Taking γw = 10 kN/m³, the vertical effective stress at 6 m depth is:
- (A) 52 kPa
- (B) 60 kPa
- (C) 72 kPa
- (D) 112 kPa
Answer: (C). Total stress = 16 × 2 + 20 × 4 = 112 kPa. Pore pressure acts only below the water table: 10 × 4 = 40 kPa. Effective stress = 112 − 40 = 72 kPa.
Q7 - Water Resources Engineering, NAT, 2 marks
A rectangular channel 4 m wide carries uniform flow 1 m deep. Manning's n is 0.02 and the bed slope is 1 in 2500. The discharge in m³/s, rounded off to two decimal places, is ____.
Answer: 3.05. A = 4 m² and P = 6 m, so R = 0.667 m. With √S = 0.02, V = (1/0.02) × R^(2/3) × 0.02 = R^(2/3) = 0.763 m/s, and Q = 4 × 0.763 = 3.05 m³/s.
Q8 - Environmental Engineering, MSQ, 2 marks
A sedimentation tank 30 m long, 10 m wide and 4 m deep treats 12 MLD. Which are correct?
- (A) The detention time is 2.4 hours
- (B) The surface overflow rate is 40 m³/m²/day
- (C) The horizontal flow-through velocity is 1200 m/day
- (D) In an ideal settling tank, discrete particles settling at 50 m/day are fully removed
Answer: (A), (B) and (D). Detention time = 1200/12,000 day = 2.4 hours. Overflow rate = 12,000/300 = 40 m/day, and an ideal tank fully removes particles settling faster than that, so (D) holds. Flow-through velocity = 12,000/(10 × 4) = 300 m/day, so (C) is false.
Q9 - Transportation Engineering, NAT, 1 mark
A car travels at 72 km/h on a level road. With a reaction time of 2.5 s, a longitudinal friction coefficient of 0.35 and g = 9.81 m/s², the stopping sight distance in metres, rounded off to two decimal places, is ____.
Answer: 108.25. At 20 m/s, lag distance = 50 m and braking distance = 400/(2 × 9.81 × 0.35) = 58.25 m, so SSD = 108.25 m.
Q10 - Transportation Engineering, MSQ, 2 marks
A traffic stream follows the Greenshields model with free-flow speed 80 km/h and jam density 120 vehicles/km. Which are correct?
- (A) The maximum flow is 2400 vehicles/h
- (B) The speed at maximum flow is 40 km/h
- (C) The density at maximum flow is 120 vehicles/km
- (D) At a density of 30 vehicles/km, the speed is 60 km/h
Answer: (A), (B) and (D). Speed is v = 80(1 − k/120), and flow q = vk peaks at half the jam density, 60 vehicles/km, so (C) is false. There v = 40 km/h and q = 2400 vehicles/h. At k = 30, v = 80 × 0.75 = 60 km/h.
Q11 - Geomatics Engineering, MCQ, 1 mark
A level reads a backsight of 1.250 m on a benchmark of reduced level 100.000 m and a foresight of 2.735 m on point P. The reduced level of P is:
- (A) 96.015 m
- (B) 98.515 m
- (C) 101.485 m
- (D) 103.985 m
Answer: (B). HI = 100.000 + 1.250 = 101.250 m, so RL of P = 101.250 − 2.735 = 98.515 m.
Q12 - Construction Materials and Management, NAT, 2 marks
Activity A (3 days) starts a project; B (4 days) and C (6 days) follow A; D (5 days) follows B; E (2 days) follows C; F (4 days) follows D and E and ends the project. The total float of C, in days, is ____.
Answer: 1. Forward pass: D ends on day 12 and E on day 11, so F starts on day 12 and the project takes 16 days, with A-B-D-F critical. Backward pass: F's latest start is 12, so E's is 10 and C's latest finish is 10. C's latest start is 4, so its total float is 4 − 3 = 1 day.
Quick answers
Where can I download GATE CE previous year papers officially?
From the official GATE Downloads page: year-wise Civil papers and keys for 2021 to 2026, and a bulk download for 2007 to 2026.
Why are there two GATE CE papers in some years?
From 2023 to 2026 Civil had two papers, CE-1 and CE-2, each with its own key; in 2026 they were the forenoon and afternoon papers.
How many marks does Engineering Mathematics carry in GATE CE?
13 of the 85 subject marks, as officially published; General Aptitude carries 15.
